A block of mass 2m is moving in the positive x-direction with velocity +4v. Another block of mass 3m is moving in the negative x-direction with velocity -v a. [5 pt] Find the velocity of the center of mass of the two block

the velocity of the center of mass of the two block is  v.

Explanation:

Hi, to answer this question we have to apply the next formula:

vcm = [ m1v1 + m2v2] / (m1+m2)

Where:

vcm =velocity of the center of mass

m1 = mass 1 , m2 = mass2

v1 = velocity 1; v2= velocity 2

Replacing with the values given:

vcm = ( 2(4v) - 3v) / (2+3) = (8v-3v) /5 = 5v/5 = v

The velocity of the center of mass of the two block is v.

Feel free to ask for more if needed or if you did not understand something.

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