3. An experiment was performed in the biomechanics lab to simulate the cardiac activity in order to investigate the relationship between blood’s viscosity and cardiac output. The experiment included a heart model which was able to generate a cardiac systolic pressure of 130 mmHg and a diastolic pressure of 85 mmHg; a set of flexible polymer tubes were used to simulate the blood vessels. The tubes had length of 200mm and dimeter ranging from 2 to 4mm in increment of 0.1mm. A fluid with viscosity similarly to that of blood (125 millipoise) was used in the experiment (1 mmHg. s = 7.5 *1e-7millipoise). Calculate and plot the viscosity resistance of the blood versus vessel radius and the cardiac output versus blood’s resistance. Discuss your findings.

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge