Physics, 08.04.2020 03:27 SunsetPrincess
Two flat conductors are placed with their inner faces separated by 15 mm. If the surface charge density on inner face A is 48 pC/m2 and on inner face B is โ48 pC/m 2 , calculate the electric potential difference โV = VA โ VB. Use วซ0 = 8.85419 ร 10โ12 C 2 /Nm2 . Answer in units of V.
(part 1 of 2) A proton is accelerated from rest through a potential difference of 25648 V. What is the kinetic energy of this proton after this acceleration? The mass of a proton is 1.673 ร 10โ27 kg and the elemental charge is 1.602 ร 10โ19 C. Answer in units of J.
(part 2 of 2) What is the speed of the proton after this acceleration? Answer in units of m/s.
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Two flat conductors are placed with their inner faces separated by 15 mm. If the surface charge dens...
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