A baseball pitcher brings his arm forward during a pitch, rotating the forearm about the elbow. If the velocity of the ball in the pitcher's hand is 34.9 m/s (about 78 mph) and the ball is 0.310 m from the elbow joint, what is the angular velocity of the forearm

112.581 rad/s.

Explanation:

Angular velocity: This can be defined as the velocity of a body undergoing angular motion. The S.I unit of angular velocity is rad/s.

From the question, The expression for angular velocity is given as,

ω = v/r Equation 1

Where ω = angular velocity of the forearm, v = velocity of the ball in the pitcher's hand, r = the distance of the ball from the elbow joint.

Given: v = 34.9 m/s, r = 0.310 m

Substitute into equation 1

ω = 34.9/0.310

ω = 112.581 rad/s.

Hence the angular velocity of the forearm = 112.581 rad/s.

i think the answer is b

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