A proton moves in a circular path perpendicular to a constant magnetic field so that it takes 0.262 × 10−6 s to complete the revolution. Determine the strength of the constant magnetic field. The angular speed is given in radians per unit time

The strength of magnetic field is 0.25 T

Explanation:

Time period sec

Mass of proton kg

Charge of proton C

Here proton moves in circular path

Velocity of proton is given by,

Put the value of velocity in above equation,

Now magnetic field is given by,

  T

Therefore, the strength of magnetic field is 0.25 T

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