There are two identical small metal spheres
with charges 22.8 µC and −16.7668 µC. The
distance between them is 6 cm. The spheres
are placed in contact then set at their original
distance.
Calculate the magnitude of the force between the two spheres at the final position. The value of the Coulomb constant
is 8.98755 × 10^9
Answer in units of N.

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-954.4N

Explanation:

Given that,

Positive charge (q1) = 22.8 µC

22.8 µC = 22.8 x 10^-6C

Negative charge (q2) = −16.7668 µC

−16.7668 µC = −16.7668 x 10^-6C

Distance between charges (r) = 6cm

convert centimetres to metres

100cm = 1m

6cm = (6/100) = 0.06m

force between the two charges (F) = ?

Recall that k is Coulomb's constant with a value of 8.98755 × 10^9 Nm2C−2

So, apply the formula for F= (kq1q2) / r²

F = (8.98755 × 10^9 Nm2C−2 x 22.8 x 10^-6C x −16.7668 x 10^-6C) / (0.06m)²

F = (-3440.55 x 10^-3Nm²) / 0.0036m²

F =(-3440.55 x 10^-3Nm²) / 3.6 x 10^-3m²

F = -954.4N

Thus, the magnitude of the force between the two spheres is -954.4 Newton.

which piece of furniture will have the most inertia and give the furniture movers the most difficulty in moving?  

answer

a 75kg dining table

its c i just checked it