There are four charges, each with a magnitude of 2.06 µC. Two are positive and two are negative. The charges are fixed to the corners of a 0.41-m square, one to a corner, in such a way that the net force on any charge is directed toward the center of the square. Find the magnitude of the net electrostatic force experienced by any charge.

0.208 N

Explanation:

We are given that

Distance,d=0.41 m

The magnitude of the net electrostatic force experienced by any charge at point 4

Net force,

Where

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle