A 12.4-g marble is dropped from rest onto the floor 1.56 m below. If the marble bounces straight upward to a height of 0.614 m, what is the magnitude of the impulse delivered to the marble by the floor

The impulse is    

Explanation:

Generally Impulse which the change in momentum  is mathematically represented as

Where m is the mass  with a value 12.4g =

            is the change in velocity which is mathematically represented as

Where s the velocity of the marble drooping and is the velocity of the marble bouncing back

setting up in a coordinate y-axis would show that is moving in the negative y-direction so the  value would be and   is moving in the positive  y-direction so the  value would be

So the formula for would be

General v i mathematically represented as

 Substituting this into the formula for

Now substituting values as given in the question

The impulse is

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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