A 28.6-kg sled is being pulled across a horizontal surface at a constant velocity. The pulling force has a magnitude of 77.3 N and is directed at an angle of 24 ° above the horizontal. Determine the coefficient of kinetic friction.

0.3

Explanation:

Coefficient of kinetic friction= frictional force /Normal reaction

normal reaction= mgcosA

m= mass=28.6kg

g =9.8m/s and A is angle 24°

Normy reaction= 28.6*9.8cos24=256N

Frictional force =77.3N

Coefficient of kinetic friction= 77.3/256=0.3

if the thermos has a vacuum innner, then heat through conv currents and conduction are reduced = vacuum flask