A weight of 15 N is located at a distance of 2.5 meters from the fulcrum of a simple lever. At what distance from the fulcrum should a weight of 20.0 N be placed on the opposite side of the fulcrum to balance the system?

The distance is 1.875 m away from the fulcrum of yhe simple lever

Explanation:

Clock wise moment = anti-clock wiseo moment.

Let's the distance to be determined be x...and let's assume x to be on the left.

15*2.5 = 20*x

37.5 = 20x

37.5/20 = x

1.875 = x

The distance is 1.875 m away from the fulcrum of yhe simple lever

no. dot product   =0 when vecs at right angles

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