Two particles are attracted to each other by the gravitational force between them. Particle 1 has a mass of 12kg, Particle 2 has a mass of 25kg. The particles are separated by a distance of 1.2m. What is the magnitude of the gravitational force acting on the particles?

1.4 x 10^-8N

Explanation:

Given that,

Mass of Particle 1 (m1) = 12kg

Mass of Particle 2 (m2) = 25kg

distance between particles (r) = 1.2m. Gravitational force (F) =

Apply the formula for gravitational force:

F = Gm1m2/r²

where G is the gravitational constant with a value of 6.7 x 10^-11 Nm2/kg2

Then, F = (6.7 x 10^-11 Nm²/kg² x 12kg x 25kg) / (1.2m)²

F = (2.01 x 10^-8Nm²) / (1.44m²)

F = 1.396 x 10^-8N (Rounded to the nearest tenth as 1.4 x 10^-8N)

Thus, the magnitude of the gravitational force acting on the particles is 1.4 x 10^-8 Newton

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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