A 2μF capacitor holds a charge of 24μC. The capacitor is discharged through a 3Ω resistor. What is the voltage across the capacitor at the time that the current through the resistor is 3A?

a. VC = 9V
b. VC = 8V
c. VC = 12V
d. VC = 3V

d. VC = 3V

Explanation:

If a 2μF capacitor holds a charge of 24μC, the voltage across the capacitor initially Vc is expressed as;

Vc = Q/C {since Q = CV}

Vc = 24μC/2μF

Vc = 12Volts

The voltage across the resistor is derived according to ohm's law;

VR = IR

Given R = 3Ω and I = 3A

VR = 3×3

VR = 9V

If the capacitor is discharged through the resistor, the voltage across the capacitor at the time that the current through the resistor is 3A is expressed as;

VC = Vc - VR

Vc is the voltage across the capacitor during discharging.

VC = 12-9

VC = 3V

because growing process had stoped after 4-5 year

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y