Part 2 needed!
An ideal gas at temperature T₀ is slowly compressed at a constant pressure...
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Physics, 06.04.2020 18:56 elrodkaitlynn8616
Part 2 needed!
An ideal gas at temperature T₀ is slowly compressed at a constant pressure of 2 atm from a volume of 10 liters to a volume of 2 liters.
Then the volume of the gas is held constant
while heat is added, raising the gas temperature back to T₀
1 atm = 1.0×10⁵ Pascals and 1 liter = 0.001 m³
Part 1:
Calculate the work done ON the gas.
The answer to the first part is
1. −800 J
2. −400 J
3. +400 J
4. +1600 J
5. −1600 J
6. +800 J
+1600 J (I have this part already)
I converted the liters to .010 m³(V₀) and .002 m³(Vₓ) (final)
and 2 atm to 2.0 * 10⁵ Pa (pressure)
W=-p(Δv)
Work= negative pressure (final-initial Volume)
-2.0*10⁵(2-10)= +1600 J
**Part 2: Is the one I need
Calculate the heat flow INTO the gas
1. +800 J
2. −1600 J
3. −400 J
4. +1600 J
5. +400 J
6. −800 J
I don't understand the formula of the Universal Ideal Gas Law
ΔU= Q+W and how to apply it to this question, Help!**
Work is W and Q is the heat I believe and applied, all I know is it has to become
Q=-W
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