Ablock slides down a frictionless plane having an inclination of 15.0 degrees. the block starts from rest at the top, and the length of the incline is 2.00 m.

a) draw a free body diagram for the block.
b) find the acceleration of the block
c) find its speed when it reaches the bottom of the incline.

part b)

a = 2.54 m/s/s

part c)

v = 3.19 m/s

Explanation:

part b)

As we know that force due to gravity along the inclined plane is given as

acceleration of the object will be given as

part c)

As we know by kinematics

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz