Physics, 03.04.2020 18:41 V3ga661

A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
can you conclude about the box? *

An unbalanced force of 25N is acting on the box.
Friction between the box and the floor is 25N to the left
The net horizontal force acting on the box is 50N.

Answers: 1

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Answer from: Justadumbemo

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, F_f , acting in the opposite direction (backward)

So the net force acting on the box is

$F_{net}=F-F_f$

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

$F_{net}=ma$

And so

F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

Which means

F_f=F

And since we are told that

F=25 N

This means that the force of friction is also 25 N:

F_f=F=25 N

Answer from: poppy4195

C.Friction between the box and the floor is 25N to the left.

Explanation:

One can conclude that the friction between the box and the floor is 25N to the left.

Frictional force is a force that opposes motion of a body. It acts in the opposite direction as the net force applied on a body.

According to newton's third law of motion "action and reaction are equal and opposite in magnitude and direction".The action force is to right and the reaction force is to the left.

Answer from: Quest

Answer: it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.explanation: we have equation of motion $s=ut+\frac{1}{2} at^2$ ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/s $s=0*t+\frac{1}{2} *2.18*t^2$ $s=1.09t^2[/ 2equating equation 1 and 2 [tex]4.75t = 1.09t^2\\ \\ t=4.36 seconds.$ so it will take 4.36 seconds to reach her average velocity 10.69 miles/hour.

Answer from: Quest

Ke reqd to move from 0 to 50 will be proportional to 50x50 or 2500. this is equal to w. to change vel from 50 to 150 you need energy prop to 22500 - 2500 = 20,000. this corresponds to 8w. best answer is a) . work reqd is prop to velocity squared.

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A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What

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