Amarble is fired horizontally from a launching device attached to the edge of a table top which is 94.0 cm above the floor. the marble then strikes the
floor 2.35 meters from the edge of the table.
what is the initial velocity of the marble as it leaves the launching device?

Time in the air of the marble using the equation y=1/2gt^2, re-arranged to make t the subject - t = √(2y/g). Therefore… t = √(0.94x2/9.81) = 0.4377…
where g=9.81.

Using the equation x=Ut (the horizontal displacement) 2.35=u x 0.4377..
re-arrange to make u = x/t. Therefore.. u=2.35/0.4377 = 5.368m/s
=5.37 = 3 significant figures

No because a circle or pie graph usually shows percentages you'd need a line graph