An ambulance is traveling north at 56.7 m/s, approaching a car that is also traveling north at 36.4 m/s. The ambulance driver hears his siren at a frequency of 726 Hz. Ambulance 56.7 m/s 36.4 m/s Car What is the wavelength at any position in front of the ambulance for the sound from the ambulance’s siren? The velocity of sound in air is 343 m/s. Answer in units of m. 002 (part 2 of 2) 10.0 points At what frequency does the driver of the car hear the ambulance’s siren? Answer in units of Hz.

Explanation:

At any position in front of the ambulance , it is source of sound which is moving at 56.7 m/s having frequency of n₀ = 726

Apparent frequency = n₀ x V /( V - Vs ) , V is velocity of sound , Vs is velocity of source

= 726 x 343 / (343 - 56.7)

= 869.77 Hz

wave length = velocity of sound / apparent frequency

=  343 / 869.77

= .394 m

b )

For observer in the car

apparent frequency

= n₀ x [(V- V₀ ) /( V - Vs )] , V₀ is velocity of observer or car

= 726 x  [(343- 36.4 ) /( 343 - 56.7 )]

= 726 x 306.6 / 286.3

= 777.47 Hz .

i think if it were me i whould divide 300 dide 15

step-by-step explanation:

b.

explanation: