La tensión en newtons necesaria para que una onda transversal cuya longitud de onda es 3.33 cm vibre a razón de 625 ciclos por segundo es:
a-9.52 x 10-8 N
b-9.52 x 10-6 N
c-9.52 x 10-4 N
d-9.52 x 10-2 N

9.34 N

Explanation:

First of all, we can calculate the speed of the wave in the string. This is given by the wave equation:

where

f is the frequency of the wave

is the wavelength

For the waves in this string we have:

, since it completes 625 cycles per second

is the wavelength

So the speed of the wave is

The speed of the waves in a string is related to the tension in the string by

(1)

where

T is the tension in the string

is the linear density

In this problem:

is the mass of the string

L = 0.75 m is the its length

Solving the equation (1) for T, we find the tension: