A Martian rover found an interesting rock that could contain signs of what Mars was like long ago. It grabbed it with its rover arm and raised it to a height of 0.2 m. Then it dropped it and found that it had a kinetic energy of 12 J when it struck the ground. Note that Mars has an acceleration due to gravity of 3.77 m/s2. Complete the following equations to determine the rock’s potential energy if it were brought to earth and dropped from a height of 1 meter. Use what you know about calculating gravitational potential energy to correctly set up and solve the equation.

Gravity bc it’s gravity

Ithink the answer would be a

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge