A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67 m, what is the spring constant?

6.22 N/m

Explanation:

F=xk  Making k the subject of the formula then

But since the applied force F is mg then we substitute mg with F is the formula hence

Converting the given mass from g to Kg, we divide it by 1000 hence m= 0.425 and taking g as 9.81 and substituting x with 0.67 m then

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered