The electric field on the surface of an irregularly shaped conductor varies from 66.0 kN/C to 26.0 kN/C. (a) Calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is greatest. nC/m2 (b) Calculate the local surface charge density at the point on the surface where the radius of curvature of the surface is smallest. nC/m2

Explanation:

We know that at pointed corner of a conductor , charge accumulate ie electric field is  maximum . Ar pointed corner , radius of curvature will be least . That is why charge leakage is greatest at pointed corner of a charged conductor.

a ) Electric field will be 26.0 kN/C at the point where radius of curvature is greatest .

b ) So electric field will be 66 kN /C at the point where radius of curvature is smallest .

the answer is a)

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air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.