An electron is accelerated from rest by a potential difference of (24.5 A) V for a distance of (4.50 B) cm. Determine the de Broglie wavelength of the electron. Give your answer in picometers (pm) and with 3 significant figures.

206 pm

Explanation:

We are given that

Potential difference,

Distance,d=

We have to determine the de Brogile wavelength of the electron.

A=11 and B=5

Charge on electron,q =

Mass of electron=m=

Speed of electron,

Using the formula

v=

de Brogile wavelength,

Where

1 pm=

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.