A 50.0 kg student climbs 5.00m up a rope at a constant speed. If the student's power output is 200.0 W, how long does it take the student to climb the rope ? How much work does the student do ?

The time taken for the student to climb the rope is 12.25 s.

The work done by the student in climbing the rope is 2,450 J.

The given parameters;

The time taken for the student to climb the rope is calculated as follows;

E = Pt

mgh = 200t

The work done by the student is obtained by applying work-energy theorem;

W = Pt

W = 200 x 12.25

W = 2,450 J

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The time taken by the student to climb is 12.25 seconds and work done is 2450 J.            

Explanation:

Given that,

Mass of the student, m = 50 kg

The student climbs to a height of 5 meters at a constant speed.

The student's power output is 200.0 W, P = 200 W

The power of an object is given by work done divided by time taken. So,

(b) W is work done,

(b)

So, the time taken by the student to climb is 12.25 seconds and work done is 2450 J.

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