A wire carrying 1.5 A passes through a 48 mT magnetic field the wire is peremndicular to the field and makes a quarter circle turn radius 21 cm in the dield regeion. Find the magnitude and direction of the magnetic force

Explanation:

Wire is in the form of an arc of the size of a quarter of a circle. The distance between its two end

=√2 x 21 cm

= 29.7 cm

= 29.7 x 10⁻² m

Force on the arc in the magnetic field will be same as the straight line meeting its two ends.

Force = BIL

= 48 x10⁻³ x  1.5 x 29.7 x 10⁻²

= 2138.4 x 10⁻⁵ N.

overcharge is the right answer system

reserve is the answer