The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate about a fixed axis. It takes 3.6 seconds to pull off 3.7 meters of cable. Assume that the cable is pulled with a constant force (constant acceleration) and that the change in the effective radius is negligible.

How many revolutions did the reel make in 3.6 seconds? (no units)

3.635

However, I am really having trouble figuring out parts B and C to this problem

B) What is the angular speed of the reel after 3.6 seconds?
(include units with answer)

C)What is the angular acceleration of the reel?
(include units with answer)

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

B)

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

     ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

to calculate the angular speed w we can use

Thus, wf=12.68rad/s

C) We can use our result in B)

I hope this is useful for you

regards

b)the angular speed after 3.6s is is 12.7rad/s

c) the angular acceleration of the reel is 3.52rad/s²

Explanation:

b)

The angle in radian is represented as follows

r = 16.2cm = 0.162m

now,

where

is the angular speed

is the angular acceleration

t is the time

the first equation of motion is represeented by

the angular speed after 3.6s is is 12.7rad/s

c)

from the above calculation , angular acceleration is calculated as

Therefore, the angular acceleration of the reel is 3.52rad/s²

i think it would be 5

answer is slate

hope this