Light with a wavelength of (465 A) nm is incident on a metal surface with a work function of (1.25 (0.1)(B)) eV. Find the maximum kinetic energy of the emitted photoelectrons. Give your answer in eV and with 3 significant figures.

The maximum kinetic energy of photoelectrons is 3.02 eV

Explanation:

Given:

Wavelength of light m

Work function eV

From the theory of photoelectric effect,

Where frequency of light, = work function its depends on nature of metal.

Now we convert energy in terms of electrovolt,

eV

Put above value,

eV

Therefore, the maximum kinetic energy of photoelectrons is 3.02 eV

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

read more on -

the answer is a)

mark brainliest