One electron collides elastically with a second electron initially at rest. After the collision, the radii of their trajectories are 0.00 cm and 2.30 cm. The trajectories are perpendicular to a uniform magnetic field of magnitude 0.0370 T. Determine the energy (in keV) of the incident electron.

63.750KeV

Explanation:

We are given that

Initial velocity of second electron,

Radius,

1 m=100 cm

Magnetic field,B=0.0370 T

We have to determine the energy of the incident electron.

Mass of electron,

Charge on an electron,

Velocity,

Using the formula

Speed of electron,

Speed of second electron,

Kinetic energy of incident electron=

Kinetic energy of incident electron=

Kinetic energy of incident electron=

1KeV=1000eV

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