A helium balloon containing 12m³ of gas at a pressure of 120kPa is released into the air. Assuming that the temperature is constant, calculate the volume the balloon would have when the pressure inside the balloon has fallen to 40kPa. Answer in m³.

The volume that the balloon would have when the pressure inside the balloon falls is 36 cubic meters.

Given the following data:

To calculate the volume the balloon would have when the pressure inside the balloon falls, we would apply Boyle's law:

Mathematically, Boyle's law is given by the formula;

Where;

Substituting the given parameters into the formula, we have;

Final volume = 36 cubic meters.

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36 m³

Explanation:

From gas laws, at a constant temperature, the product of volume and pressure are directly proportional hence expressed as p1v1=p2v2 where p is pressure while v represent volume. Subscripts 1 and 2 represent the initial and respectively. Making v2 the subject then

Substituting 120 kpa for P1, 12m³ for V1 and 40 kpa for p2 then

Therefore, the volume will be 36 m³

0.19 m/s and 0.45 m/s