A lightbulb has a resistance of 240 Ω when operating at a voltage of 120 V. What is the current through the lightbulb?

0.5Amps

Explanation:

Voltage of light bulb = 120 volts

Resistance = 240Ω

Current, I = ?

Now recall that voltage = current x resistance

i.e V = I x Rtotal

120volts = I x 240Ω

I = 120 volts / 240Ω

I = 0.5amperes

Thus, there is 0.5 Amperes of current in the light bulb.

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.

elctricity and magnet is conversion to it