A system of two objects has ΔKtot = 6 J and ΔUint = -5 J. Part A How much work is done by interaction forces? Express your answer as an integer. Part B
How much work is done by external forces?
Express your answer as an integer.

The work done by the internal forces is 5 J and the work done by the external forces is 1 J.

The given parameters;

The work done by the external forces and the internal forces is calculated as follows;

Where;

is the work done by the internal forces

is the work done by the external forces

The work done by the external forces = 1 J

The work done by the internal forces is calculated as follows;

Thus, the work done by the internal forces is 5 J and the work done by the external forces is 1 J.

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A) +5 J

B) +1 J

Explanation:

A)

The internal forces (interaction forces) acting on a system do not change the mechanical energy (sum of potential and kinetic energy) of the system.

However, these forces are responsible for converting the energy from one form into another; the work done by these forces is equal to the amount of energy converted from one form into the other.

In this problem, we have:

is the loss in potential energy of the system

is the gain in kinetic energy of the system

By looking at these numbers, this means that the internal forces have converted 5 J of energy from potential energy into kinetic energy (while the additional +1 J missing is due to external forces, as explained in part B).

Therefore, the work done by internal forces is

W = +5 J

B)

First of all, we calculate the change in mechanical energy of the system.

The mechanical energy of a system is the sum of its kinetic energy (K) and its potential energy (U):

So, the change in mechanical energy is equal to the sum of the changes of kinetic energy and the changes of potential energy:

In this problem:

So, the change in mechanical energy is:

According to the work-energy theorem, the work done by external forces on a system is equal to the change in mechanical energy of the system: therefore in this case, the work done by external forces is

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

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