If the mass attached to a spring is increased and the constant is decreased, does the period of the oscillating motion increase, decrease or stay the same

Increase

Explanation:

The period of an oscillating system is the time it takes for the system to complete 1 oscillation.

The period of a spring-mass oscillating system is given by

where

k is the spring constant

m is the mass

We see that:

- The period is proportional to the square root of the mass: so as the mass increases, the period increases too (1)

- The period is inversely proportional to the square root of the spring constant: so as the constant decreases, the period increases (2)

In this problem:

- The mass of the system is increased

- The spring constant is decreased

Therefore, according to observations (1) and (2), the period of the system will increase.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.