A 250 g car at rest rolls down a frictionless incline from a starting height of 0.75 m. What is the final velocity of the car?

3.83m/s

Explanation:

We can use the formula [ mgh = 1/2mv^2 ] to solve. We are given all variables except for "v" so that is what we need to solve for.

v = √2gh

Substitute with what we are given and simplify.

v = √2(9.8)(0.75)

v ≈ 3.83m/s

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