An air conditioner is a refrigerator with the inside of the house acting as the cold reservoir and the outside atmosphere acting as the hot reservoir. Assume that an air conditioner consumes 1.25 * 103 W of electrical power and that it can be idealized as a reversible Carnot refrigerator. If the coefficient of performance of this device is 1.75, how much heat can be extracted from the house in a day

1.89*10^8 J

Explanation:

The coefficient of performance of this device is where Q .is the useful heat supplied or removed by the considered system and W  is the work required by the considered system.

Step 1

Coeffiecient of perfromance for cooling (COPC) = 1.75 = .

                                                     Q = 1.75W

Step 2

We convert day into seconds:

1 day = 24 hrs = 86400 seconds

Step 3

Heat that can be extracted from the house in a day is:

Q = 1.75 * 1.25 * 10^3 * 86400 =  189000000 = 1.89*10^8 J

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.