One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.1 m, 0), and carries a current of 72 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 0.60 m, 0)

Explanation:

Using the magnetic field equation:

where:

= permeability of free space =

I = current in the wire

r = distance from the wire to the point

Magnetic field due to the wire on the x- axis can be calculated as:

Magnetic field due to the positive z-direction wire:

Now; adding these two vector components together to get the magnitude of the resultant vector; we have:

=

=

iron would move it is magnetic there is a mag field around the current in the wire

+15-35=-20

going in opposite directions