An ice cream truck is moving along at 20m/s (it's initial velocity.) It then speed up (accelerates) for 5 seconds at 8m/s^2. What distance would the truck travel in this time interval

The distance traveled by the truck is 200 m.

Explanation:

The expression for the equation of motion is as follows;

Here, u is the initial speed, t is the time, a is the acceleration and S is the distance.

According to the given problem, an ice cream truck is moving along at 20m/s (it's initial velocity.) It then speed up (accelerates) for 5 seconds at 8 meter per second square.

Calculate the distance.

Put u= 20 meter per second, t= 5 s and a= 8 meter per second square in the above expression.

S= 100+ 100

S = 200 m

Therefore, the distance traveled by the truck is 200 m.

the answer is 12 as i may remember

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