The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 35-cm-diameter drum spins at 1300 rpm around a vertical axis.

What is the apparent weight of a 1.1 g drop of water?

3.57N

Explanation:

given

Speed of rotation, N = 1300 rpm

diameter, d = 35 cm, so that

radius, r = 17.5 cm = 0.175 m

mass of drop = 1.1 g = 1.1*10^-3 kg

Angular speed of water, ω = 2πN/60

ω = 2π*1300/60

ω = 8169.2/60

ω = 136.15 rad/s

apparent weight will be gotten by

W(a) = mω²r

W(a) = 1.1*10^-3 * 136.15² * 0.175

W(a) = 1.1*10^-3 * 18536.82 * 0.175

W(a) = 3.57 N

Therefore, the apparent weight of 1.1 g of water is 3.57 N

d

explanation:

i think the answer is d. but im not sure!