Un bloque de 2.5kg de masa es empujado 2.2m a lo largo de una mesa horizontal sin fricción por una fuerza constante de 16.0 N dirigida a 25° debajo de la horizontal. Encuentre el trabajo efectuado por: (a) la fuerza aplicada, (b) la fuerza normal ejercida por la mesa, (c) la fuerza de la gravedad, y (d) la fuerza neta sobre el bloque

Explanation:

(a) The applied force has two components Fx and Fy. The Fx component is the only one that does work

(b) There in no net force in the vertical component

(c)

(d)

I attached an scheme of the force diagram

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not copied too! hope this !

joke:

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weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards