Someone please help :(there is one example too, please show me your work

1. A 5.00 kg bowling ball is rolling at 6.00 m/s. What is the bowling balls momentum.
2. A car with mass 1200. kg has momentum 24 000 kg m/s. How fast is the car traveling.

Example: Your physics teacher is walking at 2.00 m/s. His momentum is 300. kg m/s. What is his mass?
v = 2.00 m/s ; p = 300. kgm/s ; m = ?
p = m*v ; m = p / v ; m = (300. kgm/s) / (2.00 m/s) ; m = 150. kg

1. 30 Kg.m/s

2. 20 m/s

Explanation:

1.

Momentum is given as the product of velocity and mass, expressed by the formula p=mv where p represnt momentum in kgm/s, m represent the mass of an object in Kg and v represent the velocity in m/s. Note that for momentum, direction is critical. For the given case, since mass is given as 5kg and velocity as 6 m/s then we directly substitute to obtain momentum as p=5*6=30 kg.m/s

2

We still use the formula of momentum as p=mv but making v the subject of the formula then and substituting p with 24000 kg.m/s while m with 1200 kg we obtain that

mass and volume are the answers you are looking for

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.