A(n) 5 kg object moving with a speed of 8.7 m/s collides with a(n) 18 kg object moving with a velocity of 11 m/s in a direction 20◦ from the initial direction of motion of the 5 kg object. 8.7 m/s 11 m/s 18 kg 5 kg 20◦ What is the speed of the two objects after the collision if they remain stuck together? Answer in units of m/s.

Explanation:

Given:

Object 1:

Initial velocity, u1 = 8.7 m/s

Mass, m1 = 5 kg

Object 2:

Initial velocity, u2 = 11 m/s

Mass, m2 = 18 kg

θ = 20°

Using conservation of momentum formula,

In x component (acis of collision),

m1u1 + m2u2 × cos θ = (m1 + m2)v

In y component,

m2u2 × sin θ = 0

Inputting values in the x component and solving,

(5 × 8.7) + (18 × 11 × cos 20) = (18 + 5)v

v = 229.56/23

= 9.98 m/s

Fianl velocity of the collision, v = 9.98 m/s

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank