A 0.80 kg object tied to the end of a 2.0 m string swings as a pendulum. At the lowest point of its swing, the object has a kinetic energy of 10 J. Determine the speed of the object at the instant when the string makes an angle of 50o with the vertical.

Given,

The height of the pendulum will be:

→

By putting the values, we get

By using the conservation of energy, we get

→

Thus the response above is right.

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3.32 m/s

Explanation:

From the law of conservation of energy, the sum of mechanical and kinetic energy should be equal to the 10 J given. Potential energy is given by mgh where m is mass, g is acceleration due to gravity and h is the height. For this case, and l is string length, given as 2 m, \theta is given as 50 degrees. Kinetic energy is given by and it is this velocity that is unknown.

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therefore to conclude i would like to say that,

=more the cloud cover, the lesser the

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the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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