Ask Your Teacher Two wires, each of length 1.5 m, are stretched between two fixed supports. On wire A there is a second-harmonic standing wave whose frequency is 456 Hz. However, the same frequency of 456 Hz is the third harmonic on wire B. Find the speed at which the individual waves travel on each wire.

Explanation:

Given:

Length, L = 1.5 m

Frequency, f = 456 Hz

Velocity, v = frequency, f × wavelength, λ

At the second harmonic,

f = 2 × (v/2L)

v = 456 × 1.5

= 684 m/s

At the third harmonic,

f = 3 × (v/2L)

Where,

v = velocity

v = 2/3 × 456 × 1.5

= 456 m/s

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explanation:

i think the answer is a, hope this is right, that would be my best guess.