8. Calculate the overall rate of metabolic flux between B and C and the direction of the flux when each case below is true (consider each case independently): a. An inhibitor is used that reduces the activity of E1 by 10% b. An inhibitor is used that reduces the activity of E2 by 10% c. The activity of E2 is doubled.

a1) Direction is from B to C

a2) Rate of activity = 10pmol/10⁶ cells

b1) Activity rate = 45 pmol of C created/10⁶ cells

b2)  Activity rate=  44 pmol of B created/ 10⁶ of cells

b3) Activity rate = 80 pmol of B created/ 10⁶ of cells

Explanation:

a) E1 = 50 pmol of C

E2 = 40 pmol of B

Since E1 is greater than E2, the direction is from B to C

Rate of activity: 50pmol/10⁶ cells[B] - 40pmol/10⁶[C]

Rate of activity = 10pmol/10⁶ cells

b1) Activity of E1 reduced by 10%

Activity rate= 50 - 10% of 50

Activity rate= 50 -5

Activity rate = 45 pmol of C created/10⁶ cells

b2) Activity of E2 increased by 10%

Activity rate = E2 + 10% of E2

Activity rate= 40 + 10% of 40

Activity rate= 40 + 4

Activity rate=  44 pmol of B created/ 10⁶ of cells

b3) The activity of E2 is doubled

Activity rate = 2 * E2

 Activity rate = 2 * 40

 Activity rate = 80 pmol of B created/ 10⁶ of cells

the diagram which shows forces as either balanced = same speed or unbalanced = accelerarting

chemical properties of thing