A boat is heading due north across a river with a speed of 12.0 km/h relative to the water. The water in the river has a uniform velocity of 6.00 km/h due east relative to the ground. Determine the velocity of the boat relative to an observer standing on either bank.

Explanation:

Let speed of the boat in still water = u

speed of the river water = v

Relative speed of the boat in the water against the river flow is given by

Upstream speed = u - v ------- (1)

⇒ u - v = 12 ------ (2)

Given that speed of the water = 6

Now velocity of the boat is given From equation (2)

⇒ u = 12 + v

Put the value of v = 6 , we get

⇒ u = 12 + 6

⇒ u =  18

therefore , the velocity of the boat relative to an observer standing on either bank = u = 18

this could be newton#'s law of cooling. the cooling curve is exponential

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer