What force gives a 1.0 kg mass an acceleration of 7.0 m/s^2?

For this case we have that according to Newton's second law it is true that:

Where:

F: It is the force

m: It is the mass

a: It is the acceleration

According to the data we have:

So, we have:

Thus, the applied force will be 7 Newtons.

7N

Explanation:

From Newton's law of motion, F=ma where m is mass, a is acceleration. Since we're given mass as 1 kg and acceleration as 7 m/s2 then we substitute them directly into the above formula to get force, F.

By substitution of the above figures, F=1*7=7N

Therefore, the magnitude of force is 7N

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.