Many flashlights are powered by a stack of batteries that are slid into the end of the flashlight one after another. Suppose you have a flashlight that takes four ideal 1.5 V batteries. If the resistance of the bulb is 11 ohms, what is the current through the bulb when the flashlight is turned on

The current through the bulb when the flashlight is turned on is 0.55 A.

Explanation:

Given that,

You have a flashlight that takes four ideal 1.5 V batteries, voltage of the flashlight, V = 6 V

The resistance of bulb, R = 11 ohms

We need to find the current through the bulb when the flashlight is turned on. As per Ohms's law :

V = IR

So, the current through the bulb when the flashlight is turned on is 0.55 A. Hence, this is the required solution.                

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j