3. Through what potential difference would you need to accelerate an alpha particle, starting from rest, so that it will just reach the surface of a 15 fm diameter uranium 238 nucleus (Z-92).

The potential difference that is required to accelerate an alpha particle is .

Given the following data:

Radius =

We know that a proton has a charge of

Coulomb constant, k =

First of all, we would determine the charge on both an uranium and alpha particle.

For uranium:

For alpha particle:

Next, we would determine the potential difference that is required to accelerate an alpha particle by using this derived formula:

Substituting the given parameters into the formula, we have;

17664000 V

Explanation:

We are given that

Diameter of uranium,d=15fm

Radius,r=

1 fm=

Z=92

Charge on uranium particle= C

Because charge on proton=

Charge on alpha particle=

We have to find the potential difference would be needed to accelerate an alpha particle.

Speed of alpha particle=0

Therefore, k.E of alpha particle=0

Energy gained by alpha particle=

Where

Substitute the values

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

it doesn't. it was imagined up in the middle ages.