A resistor is connected across the terminals of a 9.0-V battery, which delivers 1.5 x 105 J of energy to the resistor in 8.0 hours. What is the resistance of the resistor

0.2592 Ω

Explanation:

From Electric Energy,

E = V²t/R Equation 1

Where E = Electric Energy, V = Voltage, R = Resistance, t = time

make R the subject of the equation

R = V²t/E Equation 2

Given: V = 9.0 V, E = 1.5×10⁵ J, t = 8 hours = 8×60 = 480 s

Substitute into equation 2

R = 9²(480)/(1.5×10⁵)

R = 81×480/150000

R = 38880/150000

R = 0.2592 Ω

Hence the resistance of the resistor = 0.2592 Ω

the answer is b, have negligible mass

c) up

hope this