An ion having charge +6e is traveling horizontally to the left at 8.30km/s when it enters a magnetic field that is perpendicular to its velocity and deflects it downward with an initial magnetic force of 7.04*10^15 N .

What is the magnitude of this field?

Magnetic field, B =

Explanation:

Given that,

Charge in the ion, q = 6e

Speed of the ion, v = 8.3 km/s = 8300 m/s

Magnetic force acting on the ion,

The magnetic force acting on the ion is given by the formula as follows :

Here,

So, the magnitude of magnetic field is .

the answer would be 32*f

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered