A 4.0-μF capacitor that is initially uncharged is connected in series with a 4.0-kΩ resistor and an ideal 17.0-V battery. How much energy is stored in the capacitor 17 ms after the battery has been connected?

2.473x10^-4J

Explanation:

C=(4x10^-6)farads, R=4000omhs, Vinital=17v, t=.017s

Use these equations τ=RC, Vfinial=Vinital(1-e^(-t/τ)), and En=

τ=(4x10^-6)(4000)=.016

Vfinial=17(1-e^(-.017/.016))=11.12v

En==2.473x10^-4J

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