A moving particle encounters an external electric field that decreases its kinetic energy from 9900 eV to 8040 eV as the particle moves from position A to position B The electric potential at A is 41.0 V and that at B is 19.0 V Determine the charge of the particle Include the algebraic sign or with your answer

No because a circle or pie graph usually shows percentages you'd need a line graph

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.

Is there any opitions? if you have the periodic table, the noble gases are 8a family, the halogen are the 7a family, and the nonmetal are  carbon, nitrogen, phosphorus, oxygen, sulfur, selenium, fluorine, chlorine, bromine, iodine and astatine.